添加二叉搜索树，以及树的先序，中序，后序递归和非递归实现

src/main/java/cn/byhieg/algorithmtutorial/BinarySearchTree.java

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+package cn.byhieg.algorithmtutorial;
+
+/**
+ * Created by byhieg on 17/3/30.
+ * Mail to byhieg@gmail.com
+ */
+
+import java.util.Stack;
+
+/**
+ * 该类是二叉搜索树
+ * 该树在实现的时候，不考虑数组中有重复的数字。
+ * 节点的左子节点的值都小于这个节点的值，节点的右子节点的值都大于等于这个节点的值
+ */
+public class BinarySearchTree {
+
+    private Node root;
+
+
+    public BinarySearchTree(){
+
+    }
+
+
+    public BinarySearchTree(int[] nums) {
+        Node[] nodes = new Node[nums.length];
+        for (int i = 0 ; i < nums.length;i++) {
+            nodes[i] = new Node(nums[i]);
+            insert(nodes[i]);
+        }
+    }
+
+    /**
+     * 查找指定的元素
+     * @param des
+     * @return
+     */
+    public Node find(int des){
+        if (root == null) {
+            System.out.println("树是空的");
+            throw new RuntimeException();
+        }
+        Node current = root;
+        while (current.data != des) {
+            if (current.data < des) {
+                current = current.right;
+            }else{
+                current = current.left;
+            }
+            if (current == null) return null;
+        }
+        return current;
+    }
+
+    /**
+     * 对BST执行插入操作，采用非递归的形式
+     * 保证插入后，左节点的值小于根节点的值，根节点的值小于右节点的值
+     * @param node
+     * @return
+     */
+    public boolean insert(Node node){
+        if (root == null) {
+            root = node;
+            return true;
+        }
+
+        if (find(node.data) != null) {
+            System.out.println("不允许插入相同data的数");
+            throw new RuntimeException();
+        }
+
+        Node current = root;
+        while (current != null) {
+            if (current.data < node.data) {
+                if (current.right == null) {
+                    current.right = node;
+                    return true;
+                }
+                current = current.right;
+            }else{
+                if (current.left == null) {
+                    current.left = node;
+                    return true;
+                }
+                current = current.left;
+            }
+        }
+        return false;
+
+    }
+
+    /**
+     * 树的前序遍历，递归实现
+     */
+    public void preOrder(Node node) {
+        System.out.print(node.data + "-->");
+        if (node.left != null) {
+            preOrder(node.left);
+        }
+        if (node.right != null) {
+            preOrder(node.right);
+        }
+    }
+
+    /**
+     * 树的中序遍历，递归实现
+     * 针对BST，该结果会从小到大输出树
+     * @param node
+     */
+    public void inOrder(Node node){
+        if (node.left != null) {
+            inOrder(node.left);
+        }
+        System.out.print(node.data + "-->");
+        if (node.right != null) {
+            inOrder(node.right);
+        }
+    }
+
+    /**
+     * 树的后续遍历，递归实现
+     */
+    public void postOrder(Node node){
+        if (node.left != null) {
+            postOrder(node.left);
+        }
+        if (node.right != null) {
+            postOrder(node.right);
+        }
+        System.out.print(node.data + "-->");
+    }
+
+
+    /**
+     * 树的先续遍历，非递归实现
+     * 1. 建立一个栈，现将头结点压入栈中。
+     * 2. 现将每出栈一个节点，打印他的值，然后都要先加入他的右节点，在加入他的左节点。因为栈的后进先出的特性，才能让左边先出。
+     * 3. 不断重复2，直到栈空
+     *
+     */
+    public void preOrder2(Node node) {
+        if (node != null) {
+            Stack<Node> stack = new Stack<>();
+            stack.push(node);
+            while (!stack.isEmpty()) {
+                Node tmp = stack.pop();
+                System.out.print(tmp.data + "-->");
+                if (tmp.right != null) {
+                    stack.push(tmp.right);
+                }
+                if (tmp.left != null) {
+                    stack.push(tmp.left);
+                }
+            }
+        }
+    }
+
+    /**
+     * 树的中序遍历，非递归实现
+     * 1. 设定cur,初始化cur = root节点，不断遍历里cur.left,并将其压入栈中，直到null。
+     * 2. 出栈一个节点，打印他的值，然后cur = node.right,并不断重复第二步
+     * 3. 当栈为空，并且cur为空时，停止
+     */
+    public void inorder2(Node node){
+        if (node != null) {
+            Stack<Node> stack = new Stack<>();
+            Node cur = node;
+            while (!stack.isEmpty() || cur != null) {
+                if (cur == null) {
+                    cur = stack.pop();
+                    System.out.print(cur.data + "-->");
+                    cur = cur.right;
+                }else{
+                    stack.push(cur);
+                    cur = cur.left;
+                }
+            }
+        }
+    }
+
+    /**
+     * 树的后续遍历，非递归实现
+     * 1. 树的先续遍历中，是栈存放顺序是根，右节点，左节点。
+     * 2. 我们可以将其反过来，用栈存放是根，左节点，右节点。然后出栈的时候，将出栈的结果存放到另一个栈里。
+     * 3. 第二栈里的顺序从上到下就是左节点，右节点，根的顺序。
+     * @param node
+     */
+
+    public void postOrder2(Node node) {
+        if (node != null) {
+            Stack<Node> stack = new Stack<>();
+            Stack<Node> result = new Stack<>();
+            Node cur = node;
+            stack.push(cur);
+            while (!stack.isEmpty()){
+                Node tmp = stack.pop();
+                result.push(tmp);
+                if (tmp.left != null) {
+                    stack.push(tmp.left);
+                }
+                if (tmp.right != null) {
+                    stack.push(tmp.right);
+                }
+            }
+
+            while (!result.isEmpty()) {
+                System.out.print(result.pop().data + "-->");
+            }
+        }
+    }
+
+
+    /**
+     * 得到树中最小的节点
+     * @return
+     */
+    public Node getMinNode(){
+        if (root == null) {
+            throw new RuntimeException("树为空");
+        }
+        Node current = root;
+        while (current.left != null) {
+            current = current.left;
+        }
+        return current;
+
+    }
+
+    /**
+     * 得到树中最大的节点
+     * @return
+     */
+    public Node getMaxNode(){
+        if (root == null) {
+            throw new RuntimeException("树为空");
+        }
+        Node current = root;
+        while (current.right != null) {
+            current = current.right;
+        }
+
+        return current;
+    }
+
+    public static class Node{
+        public int data;
+        public Node left;
+        public Node right;
+
+        public Node(int data){
+            this.data = data;
+        }
+    }
+
+    public Node getRoot() {
+        return root;
+    }
+}

src/test/java/cn/byhieg/collectiontutorialtest/BinarySearchTreeTest.java

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+package cn.byhieg.collectiontutorialtest;
+
+import cn.byhieg.algorithmtutorial.BinarySearchTree;
+import com.sun.tools.internal.ws.wsdl.document.soap.SOAPUse;
+import junit.framework.TestCase;
+import org.junit.Assert;
+
+/**
+ * Created by byhieg on 17/3/30.
+ * Mail to byhieg@gmail.com
+ */
+public class BinarySearchTreeTest extends TestCase {
+    int [] nums;
+    BinarySearchTree tree;
+    public void setUp() throws Exception {
+        super.setUp();
+        nums = new int[]{10,6,2,8,7,3,4,1};
+        tree = new BinarySearchTree(nums);
+    }
+
+    public void tearDown() throws Exception {
+    }
+
+
+    public void testInsert() throws Exception {
+    }
+
+    public void testInOrder() throws Exception {
+        System.out.println("中序遍历");
+        tree.inorder2(tree.getRoot());
+        System.out.println();
+    }
+
+    public void testPreOrder() throws Exception {
+        System.out.println("先续遍历");
+        tree.preOrder2(tree.getRoot());
+        System.out.println();
+    }
+
+    public void testPostOrder() throws Exception {
+        System.out.println("后续遍历");
+        tree.postOrder2(tree.getRoot());
+        System.out.println();
+    }
+
+    public void testGetMaxData() throws Exception {
+//        Assert.assertEquals(12,tree.getMaxNode().data);
+    }
+
+    public void testGetMinData() throws Exception {
+//        Assert.assertEquals(1,tree.getMinNode().data);
+    }
+}