Training stuff

CodeEasy/aver-prob.c

@@ -0,0 +1,33 @@
+#include <stdio.h>
+#include <stdlib.h>
+
+#define MAX 1000
+
+int main(int argc, char const *argv[]){
+
+	for(int i=1; i<MAX; i++){
+	    for(int j=1; j<MAX; j++){
+			double cont = (1+1+5+i+j)/5;
+			if(cont == 4){
+				printf("Number: %d %d\n", i, j);
+				printf("Product: %d\n", (j*i*5));
+			}
+		}
+	}
+
+	return 0;
+}
+
+/* x x x x x
+ Media = 4
+ Moda = 1
+ Mediano = 5
+	
+	Logo sabemos que o valor do meio é 5, entao:
+
+	x x 5 x x
+
+	Sabemos tambem que 1 é moda ou seja aparece 2 ou 3 vezes o valor 1
+
+	1 1 5 x x ou 1 1 5 1 x
+*/

CodeEasy/one-thounsand.c

@@ -0,0 +1,36 @@
+#include <stdio.h>
+#include <stdlib.h>
+
+#define MAX 1000
+
+int verfy(int x, int arr[]){
+	if(arr[x] != 0)
+		return 0;
+	else
+		return 1;
+}
+
+int main(int argc, char const *argv[]){
+
+	int i,j;
+	int cont=0;
+	int arr[MAX+1];
+
+	for(i=1; i<=MAX; i++){
+		arr[i] = 0;
+	}
+
+	for(i=1; i<=MAX; i++){
+		for(j=1; j<=MAX; j++){
+			if(i+j == MAX && verfy(i,arr) && verfy(j,arr)){
+				arr[i] = arr[j] = 1;
+				printf("%d + %d = %d\n", i, j, (i+j));
+				cont++;
+			}
+		}
+
+	}
+	printf("%d\n", cont);
+
+	return 0;
+}