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01. LRU Cache.py
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01. LRU Cache.py
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# https://leetcode.com/problems/lru-cache/
# Using LinkedList and Dictionary => Optimized for Interviews
# https://youtu.be/akFRa58Svug
# https://youtu.be/UudCSLREm08
class ListNode:
def __init__(self, key, value):
self.key = key
self.val = value
self.next = None
self.prev = None
class LRUCache:
def __init__(self, capacity: int):
self.capacity = capacity
self.dic = {}
self.head = None
self.tail = None
def get(self, key: int) -> int:
if key in self.dic:
self.remove(self.dic[key])
self.makeRecent(self.dic[key])
return self.dic[key].val
else:
return -1
def put(self, key: int, value: int) -> None:
if key in self.dic:
self.remove(self.dic[key])
self.dic[key] = ListNode(key, value)
self.makeRecent(self.dic[key])
else:
if len(self.dic) == self.capacity:
del self.dic[self.head.key]
self.remove(self.head)
self.dic[key] = ListNode(key, value)
self.makeRecent(self.dic[key])
def remove(self, node):
if self.head.key == node.key:
self.head = self.head.next
elif self.tail and self.tail.key == node.key:
self.tail = self.tail.prev
else:
node.prev.next = node.next
node.next.prev = node.prev
def makeRecent(self, node):
if not self.head:
self.head = node
self.tail = node
else:
node.prev = self.tail
node.next = None
self.tail.next = node
self.tail = node
# Using LinkedList and Dictionary => Optimized for Interviews
class Node(object):
def __init__(self, key, x):
self.key = key
self.value = x
self.next = None
self.prev = None
class LRUCache(object):
def __init__(self, capacity):
"""
:type capacity: int
"""
self.capacity = capacity
self.dic = {}
self.head = None
self.tail = None
def get(self, key):
"""
:type key: int
:rtype: int
"""
if key in self.dic:
node = self.dic[key]
self.makeMostRecent(node)
return node.value
else:
return -1
def put(self, key, value):
"""
:type key: int
:type value: int
:rtype: None
"""
if key not in self.dic:
# Invalidate oldest if required:
if len(self.dic) == self.capacity:
del self.dic[self.head.key]
self.removeHead()
node = Node(key, value)
self.dic[key] = node
else:
# Update the value:
node = self.dic[key]
node.value = value
self.makeMostRecent(node)
def makeMostRecent(self, node):
if self.head and self.head.key == node.key:
self.removeHead()
# Make this item the most recently accessed (tail):
if self.tail and not self.tail.key == node.key:
if node.prev:
node.prev.next = node.next
if node.next:
node.next.prev = node.prev
node.next = None
self.tail.next = node # Old tail's next is the node.
node.prev = self.tail # Node's previous is the old tail.
self.tail = node # New tail is the node.
if not self.head:
self.head = node # If this is the first item make it the head as well as tail.
def removeHead(self):
self.head = self.head.next
if self.head:
self.head.prev = None
'''
# Using OrderedDict Dictionary => Optimized but NOT for Interviews
class LRUCache:
def __init__(self, capacity):
self.dic = collections.OrderedDict()
self.capacity = capacity
self.cacheLen = 0
def get(self, key):
if key in self.dic:
ans = self.dic.pop(key)
self.dic[key] = ans # set this this key as new one (most recently used)
return ans
else:
return -1
def put(self, key, value):
if key in self.dic:
ans = self.dic.pop(key)
self.dic[key] = ans
else:
if self.cacheLen >= self.capacity: # self.dic is full
self.dic.popitem(last = False) # pop the last recently used element (lru)
self.cacheLen -= 1
self.dic[key] = value
self.cacheLen += 1
# Time Complexity = O(1) ; as search and pop operation from dictionary is of O(1)
# Space Complexity = O(N) ; for making the dictionary
'''
'''
# Using Array and Dictionary => NOT Optimized
class LRUCache:
def __init__(self, capacity):
self.capacity = capacity
self.dic = {}
self.arr = []
def get(self, key):
if key in self.arr:
i = self.arr.index(key)
res = self.arr[i]
self.arr.pop(i)
self.arr.append(res)
return self.dic[res]
else: return - 1
def put(self, key, value):
if key in self.arr:
i = self.arr.index(key)
self.arr.pop(i)
self.arr.append(key)
self.dic[key] = value
else:
if len(self.arr) >= self.capacity:
self.arr.pop(0)
self.arr.append(key)
self.dic[key] = value
# Time Complexity: O(N) ; as O(N) for searching in array and O(N) for rearranging the indexing after popping. so time = O(N) + O(N) = O(N)
# Space Complexity: O(N) ; for making the array and dictionary to store key and value
'''