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0028._Implement_Strstr.md

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28.implement strstr

难度Easy

刷题内容

原题连接

内容描述

Implement strStr().

Return the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Example 1:

Input: haystack = "hello", needle = "ll"
Output: 2
Example 2:

Input: haystack = "aaaaa", needle = "bba"
Output: -1
Clarification:

What should we return when needle is an empty string? This is a great question to ask during an interview.

For the purpose of this problem, we will return 0 when needle is an empty string. This is consistent to C's strstr() and Java's indexOf().

思路 - 时间复杂度: O(N)- 空间复杂度: O(1)******

这题直接遍历 haystack ,匹配到与 needle 第一个字符相等时,就遍历 needle,挨个比较字符。

class Solution {
public:
    int strStr(string haystack, string needle) {
        int j = 0,i = 0,index= 0;
        while(i < haystack.size() && j < needle.size())
        {
            if(haystack[i] == needle[j])
            {
                if(!j)
                    index = i;
                j++;
                i++;
            }
            else
            {
                i = ++index;
                j = 0;
            }
        }
        if(j == needle.size())
            return index;
        return -1;
    }
};