/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var sumNumbers = function (root) {
// we can track the path during DFS
// collect result when found leaf node
let sum = 0;
let currentSum = 0;
const walk = (node) => {
if (node == null) return;
currentSum = currentSum * 10 + node.val;
if (node.left == null && node.right == null) {
sum += currentSum;
}
walk(node.left);
walk(node.right);
currentSum = (currentSum - node.val) / 10;
};
walk(root);
return sum;
};